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printf("&A = %p\n",&A);

I'd recommend a cast to a pointer to void if you're using the %p conversion specifier. Sure it might seem to work how it's supposed to on most implementations even without the cast, but to be pedantic, this is undefined behavior.
The %p conversion specifier expects a pointer to void, and if any argument is not the correct type for the corresponding conversion specification, the behavior is undefined.

From the C standard draft n1570 (The fprintf function) (didn't write exactly where it is in the standard draft, because YouTube doesn't seem to like it if you put a lot of numbers in your comment) (emphasis mine):
p The argument shall be a **pointer to void**. The value of the pointer is converted to a sequence of printing characters, in an implementation-defined manner.

int x;
printf("%p", (void*)&x);